Building freeform shapes in excel (crazy stuff!) i have been programming in vba and excel since the time it first existed (yeah, i'm over 50)

The midpoint of the line segment joining points (x1, y1) and (x2, y2) has coordinates: x1+x2 2 and y1+y2 2 c a b a graph that fails the vertical

... cas, we can define this gradient formula as a function i.e.-(,,, ) =-y2 y1 mx... 1 x 2 y 2 xx 1 y 1 = −+ or as (,,, ) () () yx1 y1x 2y2mx1, y 1, x2, y 2 xx 2 y2=

You can do something like the following: read x y z tag x1 y1 z1 1 x2 y2 z2 1 x3 y3 z3 2 x4 y4 z4 2... end of data character vector all 3d-plot z y x...

(c) (2 points) compare the capacities c1 and c2 of the channels where for the rst channel, y1 = (x1 mod 10) for x1 = f1;2;;100gand for the second channel y2 = (x2...

Useful commands in stata two-stage least squares the structural form: y1 = y2 x1 x2 x3 the reduced form: y2 = x1 x3 x4.reg y1 y2 x1 x2 x3 (x1 x3 x4) check...

Showrectanglearea(x1, y1, x2, y2); } public static void showrectanglearea(double x1, double y1, double x2, double y2) { double area = math.abs((x2 - x1) * (y2 - y1));

... first[0]+last[: 7]).lower() outf.write(uname+'\n') inf.close() outf.close() note use of string methods (python 2.0 and newer) functions example: def distance(x1, y1, x2, y2...

... you could define a function func1.mthattakesas inputsx1 andx2, and returnsy1 andy2. the first line of the function definition would be: function[y1, y2]=func1(x1,x2); y1=x1...

Given any two points, say a(x1,y1) and b(x2,y2), it is possible to find the coordinates of another point p which divides ab internally if we know the ratio ap:pb.

y2 -vs -15v +15v x input ±10v fs ±12v pk y input ±10v fs ±12v pk output, ±12v pk = (x1 - x2) (y1 - y2) (scale = 1) 09040-009

Ujoining (x1,y1),(x2,y2) and another vector −→ v joining (x 1,y 1)and(x 3,y 3). let d 1 = |u| = p (x 2 −x 1) 2 +(y 2 −y 1) 2 (1) and d 2 = |v| = p (x

y2 y1 x2 x1 = m? since y 1 = mx 1 + b and y 2 = mx 2 + b, we have that y2 y1 x 2 x 1 = (mx2 + b) (mx1 + b) x 2 x 1 = m(x2 x1) x 2 x 1 = m: hence m = y2 y1 x

... pr,,50000 raise head bgz start z motion amz wait for z motion completion x0=x2 update starting x position y0=y2 update starting y position x1=x1+20000 y1=y1+20000 x2=x2+20000 y2=y2...

dots the graphics objects \psdot *[ par ]( x1, y1 ) \psdots *[ par ] ( x1, y1 ) ( x2, y2 )... ( xn, yn ) put a dot at each coordinate. whata"dot"is depends on...

When x1, y1, x2, y2 are omitted, the entire screen space becomes the default retangle. note that this command does not capture the control objects but only the

Double side1 = (x-x1)*(y2-y1) - (y-y1)*(x2-x1); double side2 = (x-x2)*(y3-y2) - (y-y2)*(x3-x2); double side3 = (x-x3)*(y1-y3) - (y-y3)*(x1-x3);

Plot(x1,x2,pch='.') # reflects dependence now consider the transformation y1 = 1 + 2*x1 y2 = -1 + 4*x2 from what distribution is y1a sample: (a) exp(1), (b) n(2,2)...

x1 y1 x1 y1 x2 y2 x3 y3 x4 y4 x1 y1 x2 y2 x3 y3 x1 y1 x2 y2 x3 y3 x4 y4 x5 y5 x7 y7 x6 y6 x1 y1 x1 x3 x1 y1 y2 x3 x1 y1 y2 x3 y4 x5 m m m m x1 y1 x1 y1 y2 x3 y3 y4 x1...

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